# Electrostatic Potential and Capacitance Class 12 Notes Physics Chapter 2

#### Chapter at a Glance

1. Electric potential is the amount of work done in bringing a unit positive charge from infinity to the point in electrostatic field. Electric Potential, V = W/q

13. If a parallel plate capacitor is charged to V volts and the charging battery is removed. A dielectric plate is now introduced between the plates of condenser, then

• (a) Charge on the condenser remains the same.
• (b) Capacity increases, becomes K times the previous value.
• (c) Potential difference between the plates decrease and becomes (1/K) times the previous value.
• (d) The field between the plates decreases and becomes (1/K) times the previous value.
• (e) Energy decreases and becomes (1/K) times the previous value i.e. U2=U/K

14. If the air capacitor is charged to V volts and dielectric plate is introduced in
the gap between the plates, (battery still connected), then

• (a) The charge on the plates increases.
• (b) The capacity increases K times.
• (c) The potential difference between the plates remains the same.
• (d) Field between the plates remains the same.
• (e) The energy increases, and becomes K times the previous value, i.e. U2=KU1

15. Force of attraction between the plates of a parallel plate capacitor is

16. If three capacitors of capacitance C1, C2 and C3 are connected in series to a potential difference V, the potential across the capacitors in the respective order will be in the ratio C2C3 : C3C1 : C1 C2.

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